A. 8

B. 4

C. 18

D. 6

If the equation of the circle passing through the origin and the points of intersection of the two circles x^{2}+y^{2}-4x-6y-3=0, x^{2}+y^{2}+4x-2y-4=0 is x^{2}+y^{2}+2ax+2by+c=0 then the ascending order of a, b,c is

The circle passing through the points (1, t), (t, 1) and (t, t) for all values of t passes through the point

The equation of the circle passing through the points of intersection of the circles x^{2}+y^{2}+2x+3y+1=0, x^{2}+y^{2}+4x+3y+2=0 and through the point (-1, 2)is

The two circles x^{2}+y^{2}+2ax+2by+c=0 and x^{2}+y^{2}+2bx+2ay+c=0 have three real common tangents, then

The points (4, -2), (3, b) are conjugate w.r.t x^{2}+y^{2}=24 if b=