If the coefficients of 2^nd, 3^rd, 4^th terms in the expansion of (1+x)²ⁿ are in A.P. then

If a is small in comparision with x, then (x/x+a)^1/2+( x/x-a)^1/2

(√2+1)⁶+(√2-1)⁶=

3.C₀-5.C₁+7.C₂-9.C₃+…………(n+1) terms =

Larger of 199¹⁰⁰+200¹⁰⁰and 201¹⁰⁰ is

The coefficient of x⁷ in (1-2x+3x²-4x³+……..∞)^-4 is

The 3^rd term of ⁴ (3x-y³)is

5^th term of (2x²+3/x)⁵ is 10. Then x=

The coefficient of xⁿ in(1+x)²/(1-x)² is

The term independent of x in (x+1/x)⁶ is