A. (3n+2)2n
B. (2n+3)3n
C. (2n+3)2n
D. (3n+2)3n
(1.02)6 + (0.98)6 =
(2-)5 + (2+)5 =
If the 3rd, 4th and 5th terms of (x+a)n are 60, 160 and 240 respectively then (x,a,n)=
C2+C4+C6+……….. =
In the expression of (x4- (1/x3))15 coefficient of x32 is equal to :