A. 0
B. nC(n/2)(-1)n/2
C. 2nCn(-1)n
D. (2n+1)Cn(-1)n
The number of non-zero terms in the expansion of (1+3√2x)9+(1+3√2x)9is equal to:
If the coefficient of rth term and (r + l)th term in the expansion of (1 + x)20 are in the ratio 1 : 2, then r is equal to:
C0+C1/2+C2/22+C3/23+.....Cn/2n
C0-2. C1+3. C2………..+(-1)n(n+1).Cn =
If the 2nd term in the expansion (13√a+a/√a-1) is 14a5/2, then the value of nC3/nC2 is
k.C0+k2.C1/2+K2. C2/3+.…………+kn+1.Cn/n+1 =
If x+y=1, then 2.nCrxr.yn-r =
2.C2+6.C3+12.C4+……….+n(n-1)Cn =
If the sum of the coefficients of (1+2x)n is 6561, then the greatest coefficient is
If (1+x+x2)n =Σr=02n rxr then a0+a2+a4+……….+a2n=