A. (m+n)Cr
B. (mn)Cr
C. (m+n)Cr+1
D. (m+n)Cr-1
Sum of the last 20 coefficients in the expansion of (1+x)39, when expanded in ascending powers of x, is
The 4th term of 6(x+2/x2)6 is
If x is so small that x2 and higher powers of x may be neglected then (1-x)1/2(1+x)2/3/(1-x)1/2
3√1003 -3√997
If n is even then C02-C12+C22-……….+(-1)n Cn2 =
The number of non-zero terms in the expansion of (1+3√2x)9+(1+3√2x)9is equal to:
If the coefficient of rth term and (r + l)th term in the expansion of (1 + x)20 are in the ratio 1 : 2, then r is equal to:
C0+C1/2+C2/22+C3/23+.....Cn/2n
C0-2. C1+3. C2………..+(-1)n(n+1).Cn =
If the 2nd term in the expansion (13√a+a/√a-1) is 14a5/2, then the value of nC3/nC2 is