A. 20
B. 10
C. 11
D. 42
mCr+ mCr-1nC1+mCr-2. nC2+………..+ nCr =
Sum of the last 20 coefficients in the expansion of (1+x)39, when expanded in ascending powers of x, is
The 4th term of 6(x+2/x2)6 is
If x is so small that x2 and higher powers of x may be neglected then (1-x)1/2(1+x)2/3/(1-x)1/2
3√1003 -3√997