The midpoint of the line segment joining (2,3,-1), (4,5,3) is

The coefficient of x⁶ in (1+x+x²+x³+x⁴+x⁵)⁶ is

The ratio of the coefficient of x¹⁵ to the term independent of x in (x²+2/x)¹⁵ is

The number of non zero terms in the expansion of (a+b)²⁰ – (a-b)²⁰ is

^mC_r+ ^mC_r-1ⁿC₁+^mC_r-2. ⁿC₂+………..+ ⁿC_r =

Sum of the last 20 coefficients in the expansion of (1+x)³⁹, when expanded in ascending powers of x, is

The 4^th term of ⁶(x+2/x²)⁶ is

If x is so small that x² and higher powers of x may be neglected then (1-x)^1/2(1+x)^2/3/(1-x)^1/2

3√1003 -3√997

If n is even then C₀²-C₁²+C₂²-……….+(-1)ⁿ C_n² =