A. 101
B. 50
C. 51
D. 204
The coefficients of three consecutive terms in the expansion of (1+x)n are in the ratio 1:7:42, then n=
Which term of (2x-3y)12 when x=1, y=5/2 numerically greatest?
If two consecutive terms in the expansion of (x+a)n are equal where n is a positive integer then (n+1)a/x+a is
If the sum of odd terms and the sum of even terms in the expansion of (x+a)n are p and q respectively then p2+q2=
If the coefficients of (2r+1)th term and (4r+5)th term in the expansion of (1+x)10 are equal then r=
If the 3rd, 4th and 5th terms of (x+a)n are 720, 1080 and 810 respectively then (x,a,n)=
xn-1 is divisible by x-k. Then the least +ve integral value of K is
The point which divides the line segment joining the points( 1,-1,2), (2,3,7) in the ratio -2:3 is
The first three terms in the expansion of (1+x+x2)10 are
C0+4.C1+7.C2+……(n+1) terms =