A. 35
B. 36
C. 39
D. 40
Let distance = x km and usual rate = y kmph
Then, (x/y) - (x/(y+3)) = 40/60 => 2y(y+3) = 9x ..... (i)
And, (x/(y-2)) - (x/y) = 40/60 => y(y-2) = 3x ..... (ii)
On dividing (i) by (ii), we get x = 40
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