A. 2 : 3
B. 3 : 2
C. 3 : 4
D. 4 : 3
Let the speed of the train be x km/hr and that of the car be y km/hr
Then, (120/x) + (480/y) = 8 => (1/x) + (4/y) = 1/15 ..... (i)
And, (200/x) + (400/y) = 25/3 => (1/x) + (2/y) = 1/24 ..... (ii)
Solving (i) and (ii), we get x = 60 and y = 80
=> Ratio of speeds = 60 : 80 = 3 : 4