A. 50
B. 100
C. 150
D. 200
Let the number of 25 p, 10 p and 5 p coins be z, 2z and 3z respectively
Then, sum of their values = Rs. [ (25z/100) + ((10x2z)/100) + ((5x3z)/100) ] = Rs. (60z/100)
=> (60z/100) = 30
=> z = 50
Hence, the number of 5 p coins = (3 x 50) = 150