A. 23 m
B. 23 (2/9) m
C. 27 (7/9) m
D. 29 m
Relative speed = (40 - 20) km/hr = [ 20 x (5/18) ] m/sec = (50/9) m/sec
=> Length of faster train = [ (50/9) x 5 ] m = (250/9) m = 27 (7/9) m
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