A. 48 km/hr
B. 54 km/hr
C. 66 km/hr
D. 82 km/hr
Let the speed of the second train be x km/hr
Relative speed | = (x + 50) km/hr |
= [ (x + 50) x (5/18) ] m/sec
= [ (250 + 5x) / 18 ] m/sec
Distance covered = (108 + 112) = 220 m
=> 200 / [ (250 + 5x) / 18 ] = 6
=> 250 + 5x = 600
=> x = 82 km/hr