The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years)

A. 8, 20, 28

B. 16, 28, 36

C. 20, 35, 45

D. 24, 42, 54

View Answer

1

Correct Answer :
16, 28, 36

Explanation :

Let their present ages be 4x, 7x and 9x years respectively

Then, (4x-8) + (7x-8) + (9x-8) = 56

=> 20x = 80

=> x = 4

=> Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively

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