The orthocentre of the triangle formed by the points(2,1,5), (3,2,3), (4,0,4) is
The in-centre and ex centre of the triangle formed by the lines 3x+4y=0, 5x-12y=0, y=15 are
The points 2a-b+3c, -a+2b-4c, 12a-b-3c, 6a+2b-c lie in a plane. Then the vector equation of the plane is
Let A(-2,3), B (-7,5), C (3,-5) are three vertices of a triangle and area of the triangle ABC is P and Area of the triangle formed by the midpoints of AB, BC, CA is Q and area of the triangle formed by two vertices and centroid is R then decreasing order of P, Q,R is
The shortest distance between the straight line passing through the point A=(6, 2, 2) and parallel to the vector(1, -2, 2) and the straight line passing through A’=(-4, 0, 1) and parallel to the vector (3, -2, -2) is